Question

p can do a work 3 times faster than q and therefore takes 40 days less than q. find the time in which p and q can complete the work individually.

Answer 1

Let the no. of days taken by ‘p’ to complete the work is denoted by D

P works 3 times faster than q.

Therefore, no. of days taken by q = 3D

Since p completes the work in 40 days lesser than q, D = 3D-40

= > 2D= 40

D = 20

So, p takes 20 days to complete

Q takes 20 x 3 = 60 days to complete the same work

Combined work of p and q can be calculated by taking L.C.M

20 x 60 / (20 + 60) = 15

So, p and q together will take 15 days to complete the work

Answer 2

Answer:

15

Step-by-step explanation:

15 Days

To answer this question, first of all we must find out the number of days taken by each person to finish the work.

Let the number of days taken by be x and the number of days taken by be 3x.

We know the difference between the days taken by both of them is 40. So we can write-

3x - x = 40

This gives us x = 20 and 3x = 60

So the number of days taken by to finish the work is 20 and by is 60

Now, according to the information given in the question, we know that is three times faster tha . So, we can say that =

Time taken by Y to finish the work = 60 days

and together = 3 + =

Time taken by 4 to finish the job is 60/4 days i.e. 15 days.