Question

p can do a work in 6 days. working with q, the work is completed in 7 days. if p starts work and p and q sequentially after one day, q alone can complete the work in how many days? ​

Answer 1

Answer:

• Q can alone complete work in 9 days.

Given :

• P can do a work in 6 days.

• Both completed the work in 7 days.

To find :

• Q can alone complete work =?

Step-by-step explanation:

P = 1/6

P + Q = 7 days

P part first,

P works on 1, 3, 5, 7 day

P works for 4 days and Q works for 3 days.

So, P = 4² × 1/6³ = 2/3

Remaining = 1/3 part

So, Q do 1 parts work in 3 days.

Total 3 parts = 3 × 3 = 9 days.

Thus, Q can alone complete work in 9 days.

Answer 2

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