Question

p Cube + 27 q cube + 125 R cube - 45 pqr​

Answer 1

$\huge\underline\mathtt\red{Answer:}$

$p {}^{3} + 27q {}^{3} + 125r {}^{3} - 45pqr$

$= p {}^{3} + (3q) {}^{3} + (5r) {}^{3} - 3(p \times 3q \times 5r)$

$(p + 3q + 5r) {}^{3}$