Chemistry, asked by Anonymous, 10 months ago

p-Dichlorobenzene has higher m.p. and solubility than those of o-and m-isomers. Discuss

5 mark question , long answer only​

Answers

Answered by MajorLazer017
8

Answer :-

The melting point of p-isomer of dichlorobenzene is higher than that of o-and m-isomers. This is because, p-isomer has symmetrical structure therefore, its molecules can easily be packed closely in crystal lattice.

Hence, it has stronger intermolecular forces of attraction than o-and m-isomer. Therefore, greater energy is required to break the intermolecular forces to melt or dissolve the p-isomer than the corresponding o-and m-isomers. In other words, the melting point of p-isomer is higher and its solubility is lower than the corresponding o-and m-isomers.

Answered by Anonymous
0

In case of dichlorobenzenes, para isomer is more symmetrical than ortho and meta isomers.

Hence, in the crystal lattice, para isomer fits more closely than ortho and meta isomers.

Due to this, more energy is required to break the crystal lattice of para isomer.

Hence, p-Dichlorobenzene has higher melting point than those of o- and m-isomers.

p-Dichlorobenzene has higher m.p. and lower solubility than those of o- and m-isomers. ... p-Dichlorobenzene is more symmetrical than o-and m-isomers. For this reason, it fits more closely than o-and m-isomers in the crystal lattice. Therefore, more energy is required to break the crystal lattice of p-dichlorobenzene.

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