Question

p. e =2k. e , a. at height 2h/3,b.at height h/3,c.at height h/2​

Answer 1

Answer:

Explanation:

From law of conservation of energy, the total energy of a system is conserved. Hence at all points, TE+KE=constantTE+KE=constant

Hence d\rightarrow fd→f.

When the PE=KEPE=KE, half the total energy is converted to kinetic energy. Hence the initial potential energy has dropped to half. Therefore the ball must have fallen by h/2h/2.

Hence a\rightarrow ea→e

When the PE=2KEPE=2KE, one third the total energy is converted to kinetic energy. Hence the initial potential energy has dropped to two-third of it Therefore the ball must have fallen by h/3h/3.

Hence b\rightarrow gb→g

When the 2PE=KE2PE=KE, two third of the total energy is converted to kinetic energy. Hence the initial potential energy has dropped to one third. Therefore the ball must have fallen by 2h/32h/3.

Hence c\rightarrow hc→h