P(E)=4/5 find p(E) plz answer
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P(E) + P(E') =1
4/5 + p(E')=1
P(E)'= 1-4/5
P(E') =1/5
4/5 + p(E')=1
P(E)'= 1-4/5
P(E') =1/5
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P(E)=1-P(E)
P(E)=1-4/5
P(E)=5-4
_______
5
P(E)=1/5
I HOPE it helps TO U
P(E)=1-4/5
P(E)=5-4
_______
5
P(E)=1/5
I HOPE it helps TO U
when the p(E)=4/5 we can be find the probability so p(E')+P(E)=1, But this was not proper so we sended P(E) into right side now we get P(E')=1+P(E) ,SO WKT ,P(E')=1+4/5, We must and should take the LCM SO,, NOW WE GET P(E')= 5-4/5, P(E')=1/5 NOW U UNDERSTAND
sorry P(E')=1-P(E)
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