Question

(P->Q)->(^Q) is ____​

Answer 1

Answer

Correct option is

(p∧q)→r

P→(∼q→r)

=p→(∼q∨r)

∼p∨(∼q∨r)

(∼p∨∼q)∨r

∼(p∧q)∨r

(p∧q)→r