P has 40 elements,P∪Q has 60 elements and P∩Q has 10 elements, then how many elements does Q have
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ANSWER
n(P)=40
n(P∪Q)=60
n(P∩Q)=10
n(P∪Q)=n(P)+n(Q)−n(P∩Q)
60=40+n(Q)−10
n(Q)=60−40+10
n(Q)=30
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