∆P is 150° in exterior ∆R is 40° in interior ∆Q is x in exterior, find x
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Given:-
∆P is 150° in exterior ∆R is 40° in interior ∆Q is x in exterior, find x
Solution:-
angle pqr = 150° ( alternate interior )
so, 150 + x = 180
x = 180 - 150
x = 30
FINAL ANSWER
x = 30
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