Question

P is a centre the circle with radius 18cm .If the area of the triangle PQR is 100 cm².Find central angleQPR

Answer 1

Answer:

In the given figure, PQR = 100 , where P, Q and R are points on a circle with centre O. Find OPR. ... So, PQR + PSR = 180 100 + PSR = 180 PSR = 180 100 PSR = 80 Arc PQR subtends POR at centre of circle.

Answer 2

Answer:

Area of ∆ = 1/2* side1 * side2 * sin@ (where @ is angle between the two sides s1 & s2)

here s1 = s2 = 18cm (since radius are equal)

so,

100 = 1/2 * 18 * 18 * sin@

100/162 = sin@

50/81 = sin@

@ = sin^(-1)(50/81) (Ans)

(Mark as brainlist)