Question

P is a external point of circle with center with centers. after joining OP what is the next step to draw the pair of tangents of circle from P?​

Answer 1

Answer :

⇒2PQ=PO

Step-by-step explanation:

Given ∠QPR=120

0

Radius is perpendicular to the tangent at the point of contact.

∴∠OQP=90

0

⇒∠QPO=60

0

(tangent drawn to a circle from an external point are equally inclined to the segment, joining the center to that point).

In ΔQPO,cos60

0 = PO PPQ⇒ 21

=

PO

PQ

⇒2PQ=PO

if you understood thanks

Answer 2

Step-by-step explanation:

Draw perpendicular bisector of OP.

Then taking the point of intersection O' (or any alphabet you want) as centre and radius O'P draw another circle.

From point P draw a line where the second circle touches the first circle