P is a external point of circle with centre O. After joining OP what is the next step to draw the pair of tangents of circle from p?
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Answer:
Given ∠QPR=120
0
Radius is perpendicular to the tangent at the point of contact.
∴∠OQP=90
0
⇒∠QPO=60
0
(tangent drawn to a circle from an external point are equally inclined to the segment, joining the center to that point).
In ΔQPO,cos60
0
=
PO
PQ
⇒
2
1
=
PO
PQ
⇒2PQ=PO
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