Question

p is a point equidistant from two lines l and m intersecting at point a show that angle bpa = angle cpa​

Answer 1

Answer:

You are given that lines l and m intersect each other at A.

Let PB is perpendicular on l and

PC⊥m. It is given that PB=PC.

You need to show that ∠PAB=∠PAC.

Let us consider △PAB and △PAC. In these two triangles,

PB=PC (Given)

∠PBA=∠PCA=90

∘

(Given)

PA=PA (Common side)

So, △PAB≅△PAC (RHS rule)

So, ∠PAB=∠PAC(CPCT)

Answer 2

ANSWER IS IN THE ABOVE IMAGE .

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