Math, asked by bharathi5638, 21 days ago

P is a point lying outside a line I. M is a point on I which is nearest to P. If A and B are points
on I, different but equidistant from M, then prove that PA = PB.​

Answers

Answered by itzluciferr
8

\huge\underline\red{Answer:}

\small\green{PM \:  will \:  be \:  minimum \:  when \:  PM \:  is}

\small\green{perpendicular \:  on \:  line \:  l.}

\small\green{∴ ∠PMA = ∠PMB = 90°}

\small\green{AM = BM \:  (given)}

\small\green{MP = MP \:  (common \:  side)}

\small\green{∴∆ \: PMA ≅ ∆ \: PMB}

\small\green{(By \:  S-A-S) }

 \small\green{Hence, PA = PB}

\huge\underline\red{Explanation:}

\small\underline\green{Hope \:  this \:  answer \:  will \:  help \:  you.}

\small\underline\green{Plz \:  mark \:  me \:  as \:  a \:  Brainliest.}

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