Question

P is a point on bc of triangle, prove that (ab+bc+ac) >2(ap)

Answer 1

Answer:

In△ABP,AB+BP>AP

In△APC,PC+AC>AP

Now, add the corresponding sides.

(AB+BC+AC)>2AP.

Answer 2

Answer:

ab+bp > ap-1

ac+cp > ap-2

1+2

ap+bp+cp+ac > ap+ap

ap+bc+ac >2ap

Ans=2ap