P is a point on the bisector of ∠ABC. If the line through P, parallel to BA meet BC at Q, prove that BPQ is an isosceles triangle.
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It is given that,
Angle 1 = Angle 2 ( due to bisector )
AB||BP
So,
We can say that,
Angle 1 = Angle 3
But, we know that
Angle 1 = Angle 2
So from this we can say that,
Angle 2 = Angle 3
So BQ=PQ ( due to equal angles)
So BPQ is an isosceles triangle.
Hope it will help you.....
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