Question

P is a point on the line segment joining A(3,4) and (6,-2) such that 5AP =2BP. find the coordinates of P. plz solve

Answer 1

Answer

Given 5ap=5pb

This gives that the ratio is 5:2

let P(x,y)

Now, by using ratio formula

X={5(6)+2(3)}/5+2

X= {30+6}\7

X=36/

Again y={5(-2)+2(4)}\5+2

Y= (-10+8)/7

Y=. (-2/7)

Now the coordinates of point p(x,y) =(36/7,-2/7

Hence solved

Thanku for this question

Answer 2

Answer:

Step-by-step explanation:

Given

A=(3,4)

B=(6,-2)

5AP = 2BP

Let P(x,y) be the point on the line

Formula ((mx2+nx1 ) / m+n ) , ((my2+ny1) / m+n)

5AP = 2BP  

AP / BP = 2/5-

A(3,4) is (x1,y1)           B(6,-2) is x2,y2

m = 2 n = 5  

Substitute in formula

[[(2(6) + 5(3)] /5+2 ) , ([2(-2) + 5(4)] / 5+2) ]

[[12+15] / 7 , [-4+20] / 7]

[27/7 , 16/7 ]

So the coordinates of P are [ 27/7 , 16/7]

Hope this helps you!!!!!

Thank you