Question

P is a point on x-axis and A (20,20) is a point such that PA=29. Find the coordinates of P.

Answer 1

Step-by-step explanation:

p is (x, 0)

A(20,20)

and AP=29

PA=√(20-x)2+(20-0)2

29=√400-40x+x2+400

squaring both sides

(29)2=800-40+x2

841=800-40x+x2

x2-40x-41=0

x2-x-41x-41=0

x(x-1) -41(x-1) =0

(x-1)(x-41) =0

coordinates of P=(1,0) Or (41,0)