Question

P is a point which is equidistant from A(3,4) and. B (5,-2) . Find the co-ordinates of P , if the area of the triangle APB= 10units​

Answer 1

Answer:

$x= \frac{x2 + x1}{2}$

$x = \frac{5 + 3}{2}$

$x = 4$

$y = \frac{y2 + y1}{2}$

$y = \frac{ - 2 + 4}{2}$

$y = 1$

Therefore, P(x, y) = 4,1

Answer 2

Answer:

Heyy sissy.,❤

DP super⚠️