p is a point which is equidistant from two line L and M intersection at point A .psove that the line A bisecls the angle between them
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You are given that lines l and m intersect each other at A.
Let PB is perpendicular on l and
PC⊥m. It is given that PB=PC.
You need to show that ∠PAB=∠PAC.
Let us consider △PAB and △PAC. In these two triangles,
PB=PC (Given)
∠PBA=∠PCA=90
∘
(Given)
PA=PA (Common side)
So, △PAB≅△PAC (RHS rule)
So, ∠PAB=∠PAC(CPCT)
hope this helps you
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One group of these derivatives is composed of salts containing the phosphate ion (PO43−), the hydrogen phosphate ion (HPO42−), or the dihydrogen phosphate ion (H2PO4−), and positively charged ions such as those of sodium or calcium; a second group is composed of esters, in which the hydrogen atoms of phosphoric acid .
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