Question

P is any point in the interior of triangle ABC. Which of the following are true statements.
a. BP+PC>BC
b. AP+PC<AC
c. AP+AB>BP
Explain with reasons ​

Answer 1

Answer:

thus, BP=CP

And AP bisects ∠BAC

Step-by-step explanation:

Given ABC is a trianlge in which AB=AC . P is any point in the interior of the triangle such that angle ABP=ACP

In ΔAPB and ΔAPC,

AB=AC[given]

∠ABP=∠ACP [given]

AP=AP[common]

ΔAPB≅ΔAPC[by SAS congruency criterion]

∴∠PAB=∠PAC [corresponding angles of congruent trianlges]

thus, BP=CP

And AP bisects ∠BAC

Answer 2

your quesion Answer is (a)and (c)is right