P is any point on base BC of ∆ABC and D is the mid point of BC. DE is drawn parallel to PA to meet AC at E. If ar (∆) = 12,then find area of ∆.
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Answer:
triangle epc =6cm²
Step-by-step explanation:
Given that: triangle abc =12cm²
ABC is a triangle and D is the mid-point of BC and P is a point on BC such that DE||PA.
so ar(epc)=1/2 ar(abc)
since ar(abc)=12cm²
then, ar(epc)=1/2×12
=6cm²
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