Question

P is equal to angle ACD show that angle abc is equal to angle ADB fig=triangle
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Answer 1

Answer:

In △ABC, we have

AB=AC⇒∠ABC=∠ACB

(angles opposite to equal sides.)

Again in △DBC, we have

DB=DC ......... (given)

⇒∠DBC=∠DCB (angles opposite to equal sides).

Hence we obtain

∠ABC−∠DBC=∠ACB−∠DCB.

This gives

∠ABD=∠ACD. [henceproved]