Question

P is four times as efficient as q. p can complete a work in 45 days less than q. if both of them work together, then in how many days the work will be completed?

Answer 1

Let P completes the work in x days

as P is 4 times efficient than q ; q takes 4x days to complete the work

now 4x - x = 45

3x = 45

x = 15 days

so p takes 15 days to complete the work

and q takes 4x days i.e. 4×15 = 60 days

now both can complete the work in one day

= 1/15 + 1/60 = 75 / 15 × 60

= 1/12 work

so total 12 days required to complete the work

Answer 2

Answer:

12

Step-by-step explanation:

P:Q=4:1 (efficiency)

4-1=3 (difference in their efficiencies)

3unit=45

1unit=15

p= 4*15=60

q=1*15=15

total work= 60 (will take as reference to p)

4+1=5 (sum of their efficency)

60/5= 12