P is four times as efficient as q. p can complete a work in 45 days less than q. if both of them work together, then in how many days the work will be completed?
Answers
Answered by
15
Let P completes the work in x days
as P is 4 times efficient than q ; q takes 4x days to complete the work
now 4x - x = 45
3x = 45
x = 15 days
so p takes 15 days to complete the work
and q takes 4x days i.e. 4×15 = 60 days
now both can complete the work in one day
= 1/15 + 1/60 = 75 / 15 × 60
= 1/12 work
so total 12 days required to complete the work
as P is 4 times efficient than q ; q takes 4x days to complete the work
now 4x - x = 45
3x = 45
x = 15 days
so p takes 15 days to complete the work
and q takes 4x days i.e. 4×15 = 60 days
now both can complete the work in one day
= 1/15 + 1/60 = 75 / 15 × 60
= 1/12 work
so total 12 days required to complete the work
Answered by
0
Answer:
12
Step-by-step explanation:
P:Q=4:1 (efficiency)
4-1=3 (difference in their efficiencies)
3unit=45
1unit=15
p= 4*15=60
q=1*15=15
total work= 60 (will take as reference to p)
4+1=5 (sum of their efficency)
60/5= 12
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