Question

p is mid point of side BC of triangle ABC .Q is the mid point of AP . BQ when produced meets AC at L . prove that AL =1\3AC

Answer 1

this is the complete solution...

Answer 2

Explanation:

we need to draw PS parallel to BL

from the figure  Δ BCL, P is the mid-point of BC and PS is parallel to BL.

Where, S is the mid-point of CL

So, CS=SL  ----- (1)

Again, In Δ APS, Q is the mid-point of AP and QL  is parallel to PS.

Where, L is the mid-point of AS.

So,   AL=LS ----- (2)

From equations (1) and (2),

We get, AL = LS = SC

⇒ AC= AL+LS+SC

⇒ AC= AL+AL+AL

⇒ AC=3AL

∴ AL= 1/3AC

Learn more:

https://brainly.in/question/2402085

∴ AL= 1/3AC