Question

P is the centre of circle and segment PQ is a tangent to circle at midpoint M if Q is equal to 30 and PQ is equal to 34 then find the radius of the circle​

Answer 1

Step-by-step explanation:

Radius of circle =

${(34)}^{2} = {(30)}^{2} + {r}^{2} \\ r = \sqrt{ {34}^{2} - {30}^{2} } \\ = \sqrt{1156 - 900} \\ = \sqrt{256}$

= 16 cm

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Answer 2

Answer:

the point where. chord and tangent meet is always 90°

By applying Pythagoras theorum

H^2=p^2+b^2

(34)^2=p^2+(30)^2

1156-900=p^2

256=p^2

16cm = p

so PM=16cm