Question

P is the centre of the circle whose
radius is 10 cm find the clistance of
the chord from the centre it the length
of the chord is 12 cm,
e chord 10 crite of​

Answer 1

Answer:

Step-by-step explanation:

The radius divides the chord into two equal parts.

Let the length of the chord be AB.

Let point P be the point where the radius cuts the chord.

The lengths:

AP = BP

We divide this by 2 to get :

12/2 = 6 cm

The radius to the point where the chord cuts the circle gives the hypotenuse of the right angled formed.

Since the radius is 10 cm we have a right angled triangle whose sides are as follows :

a = h

b = 6

c = 10 cm

By Pythagoras theorem we can get the length a = h

We apply this as follows :

10^2 - 6^2 = 64

h = Square root of 64 = 8

So the distance of the chord from the center is 8 cm.