Question

P is the exterior Of point (0,9). A tangent from P touches the circle at T.If PT= 40,then OP=??

Answer 1

We know, tangent of circle at point of contact making right angle with the radius.

Hence, using Pythagoras Theorem in △OTP,

OT

2

+PT

2

=OP

2

15

2

+8

2

=OP

2

OP

2

=125+64=189

OP=17 units

I hope it is help you please give me a brianliest mark brother

Answer 2

Answer:

Step-by-step explanation:

in triangle otp - $ot^{2}$+$op^{2}$=$pt^{2}$

∴$9^{2}$+$op^{2}$=