P is the midpoint of the part of the line
3x+y-2=0 intercepted between the axes. Then
the image of P in origin is
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Answer:
P(-1/3,-1)
Step-by-step explanation:
Equation of given straight line is 3x + y -2=0
=> 3x/2 + y/2 =1
=> x/(2/3) +y/2 = 1 , from this it is clear that the given straight line intersects x axis and y axis at (2/3 ,0) & (0,2). The middle point of the intercepted P { (2/3+0)/2 ,( 0+2)/2}=> (1/3 ,1) is in the 1st quadrant, so,the image of P in origin (0,0) will be in third quadrant at (-1/3,-1)
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