P is the point (h, 7) P lies on the line 3y+2x = 5. a) find the value of h
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Answered by
2
Answer:
Correct option is
D
4
∣PA−PB∣<AB
∣PAPB∣
max
=AB
In this case P, A & B are collinear
So 'P' is intersecting point of these two lines as shown in figure
Equation of AB:
y−x
2x+3y
=1
=5
}
⇒ Intersection point P(
5
2
,
5
7
)
∴3h+2k=4
Step-by-step explanation:
Answered by
2
Answer:
value of h is 4
Step-by-step explanation:
PA−PB∣<AB
∣PAPB∣
max
=AB
In this case P, A & B are collinear
So 'P' is intersecting point of these two lines as shown in figure
Equation of AB:
y−x
2x+3y
=1
=5
}
⇒ Intersection point P(
5
2
,
5
7
)
∴3h+2k=4
solution
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