Question

P is the point in the exterior of the circle O and radius the tangents from the P to the circle touch the circle at X and Y. Find OP, if r=12 ,XP=5.​

Answer 1

Answer:

ANSWER

Since tangent is perpendicular to the radius through the point of contact

so, PQ⊥OQ

therefore

(PQ)

2

+(OQ)

2

=(OP)

2

=(5)

2

+r

2

=(13)

2

=r

2

=169−25

⇒r

2

=144

⇒r=12cm

so, diameter of the circle 2×r

=2×12 =24cm