P is the point of minor arc AB of a circle with center Om if mAB=110° and m(AP)=80°, what is m(PB)
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Given : P is the point of minor arc AB of a circle with center O . mAB=110° and m(AP)=80°
To find : m(PB)
Solution:
mAB=110°
110° is less than 180 °
P lies on on minor arc AB
Center of Circle = O
mAB = 110°
mAB = mAP + m(BP)
=> 110° = 80° + m(BP)
=> m(BP) = 30°
m(BP) = 30°
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