Question

"P" is twice as old as "R" was two years ago. If the differences between their ages is 2 years, how old is "P" today?(a)6 years (b)8years (c)10years (d)12years.

Answer 1

Let x years and y years be the present ages of 'P' and 'R' respectively.

Two years ago, P's age = (x - 2) years

Two years ago, R's age = (y - 2) years

Now, we shall apply, the first condition;

(x - 2) = 2×(y -2)

or, x - 2y = - 2 -------------(1)

Now, we shall apply, the second condition;

x - y = 2 -----------------------(2)

Now subtract equation (2) from equation (1), we get,

y = 4 years

Again, substitute y = 4 in equation (1), we get

x = 6 years

Hence, the present age of 'P' is 6 years

Therefore, the given option (a) 6 years is the correct option.

Answer 2

As per the statement,

P = 2 * R

If the difference is 2 then P – R = 2

2R – R = 2

R = 2

Then the total of the age will come as P = 2R

P = 2 * 2 = 4 years

However, the questions are incomplete since there is no mention that the difference is in the actual age or old age.