Question

P is twice good as q. Together, they finish the task in 22 days. In how many days can q alone do the same work

Answer 1

Answer:

Q alone can do the same work in 66 days

Step-by-step explanation:

Let P can complete a task in x days.

Then, Q can complete the task in 2x days

$implies$

P's 1 day work $=\frac{1}{x}$

Q's 1 day work $=\frac{1}{2x}$

$\implies$

(P+Q)'s 1 day work

$=\frac{1}{x}+\frac{1}{2x}$

$=\frac{2+1}{2x}$

$=\frac{3}{2x}$

$=\frac{1}{\frac{2x}{3}}$

$\implies$ P and Q together can complete a task in $\frac{2x}{3}$ days

$\implies\:\frac{2x}{3}=22$

$\implies\:\frac{x}{3}=11$

$\implies\:x=33$

$\therefore$ Q alone can do the same work in 66 days