p is vertex of cuboid and q r and s are three points on the adjacent edge passing through p as. pq=pr=2cm and ps =1cm. then the area of ∆qrs(in cm2) is
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0
Answer:
4
Step-by-step explanation:
Given that:
QP=8cm,PR=6cm and SR=3cm
(I) In △PQR and △SPR
∠PRQ=∠SRP (Common angle)
∠QPR=∠PSR (Given that)
∠PQR=∠PSR (Properties of triangle )
∴△PQR∼△SPR (By AAA)
(II)
SP
PQ
=
PR
QR
=
SR
PR
(Properties of similar triangles)
⇒
SP
8cm
=
3cm
6cm
⇒SP=4cm and
⇒
6cm
QR
=
3cm
6cm
⇒QR=12cm
(III)
ar(△SPR)
ar(△PQR)
=
SP
2
PQ
2
=
4
2
8
2
=4
Answered by
0
Answer:
Step-by-step explanation:
Answer in the following picture , umm can u pls mark me as brainliest please ??
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