Math, asked by dev904756, 6 months ago

p के किस मान के लिए px2+4x+1=0 वास्तविक और असमान मूल है

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Answered by omund34

2

Answer:

$px2 + 4x + 1 = 0 \\ px2 = - (4x + 1) \\ p = \frac{ - (4x + 1)}{2x}$

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