Question

p^ka of acetic acid = 4.76 and p^kb of ammonium hydroxide = 4.75. calculate the pH of ammonium acetate solution

Answer 1

pH=7+1/2(pka-pkb)

= 7+1/2(0.01)

=7.005

Answer 2

$\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\purple{R}}}}$

• ❤..${pH}$=$+{1/2[pka - pkb]}$
• =${7+1/2[4.76-4.75]}$
• =${7+1/2[0.01]=7+0.005=7.005}$