Math, asked by deepikarawat738, 3 months ago

p ke kis maan ke liye bahupad x2-2x-(7p+3) ka ek soonayak h​

Answers

Answered by prchau65
0

Answer:

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Answered by nithinkumarjb
0

Answer:

p =3

Step-by-step explanation:

p(x)=x^2-2x-(7p+3)

p(-4)=(-4)^2-2×-4-(7p+3)=0

=16+8-7p-3=0

-7p=-21

p=-21/-7

=3

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