p ke kis maan ke liye bahupad x2-2x-(7p+3) ka ek soonayak h
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p =3
Step-by-step explanation:
p(x)=x^2-2x-(7p+3)
p(-4)=(-4)^2-2×-4-(7p+3)=0
=16+8-7p-3=0
-7p=-21
p=-21/-7
=3
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