p ki power 4 -(p+q)ki power 4
Answers
Answered by
50
Hello Mate!
= p⁴ - ( p + q )⁴
= (p²)² - [( p + q )²]²
= [ p² + ( p + q )² ][ p² - ( p + q )² ]
= [ p² + p² + q² + 2pq ][( p + p + q )( p - p - q )]
= ( 2p² + q² + 2pq )( 2p + q )( - q )
= - q ( 2p² + q² + 2pq )( 2p + q )
Have great future ahead!
= p⁴ - ( p + q )⁴
= (p²)² - [( p + q )²]²
= [ p² + ( p + q )² ][ p² - ( p + q )² ]
= [ p² + p² + q² + 2pq ][( p + p + q )( p - p - q )]
= ( 2p² + q² + 2pq )( 2p + q )( - q )
= - q ( 2p² + q² + 2pq )( 2p + q )
Have great future ahead!
Answered by
32
Given polynomial :
p⁴ - ( p + q )⁴
To Do :
Simplify
Simplification :
= p⁴ - ( p + q )⁴
= (p²)² - {( p + q )²}²
= {p² + ( p + q )² }{p² - ( p + q )²}
= {p² + p² + q² + 2pq }{( p + p + q )( p - p - q )}
= ( 2p² + q² + 2pq )( 2p + q )( - q )
= - q( 2p² + q² + 2pq )( 2p + q )
What is a polynomial ?
=> An algebraic expression which is having the exponent of each and every term as a whole number.
Eg : 2 , 6x , X+2y
★ AhseFurieux ★
p⁴ - ( p + q )⁴
To Do :
Simplify
Simplification :
= p⁴ - ( p + q )⁴
= (p²)² - {( p + q )²}²
= {p² + ( p + q )² }{p² - ( p + q )²}
= {p² + p² + q² + 2pq }{( p + p + q )( p - p - q )}
= ( 2p² + q² + 2pq )( 2p + q )( - q )
= - q( 2p² + q² + 2pq )( 2p + q )
What is a polynomial ?
=> An algebraic expression which is having the exponent of each and every term as a whole number.
Eg : 2 , 6x , X+2y
★ AhseFurieux ★
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