Math, asked by nishantmehta12057, 11 months ago

p lez tell me the answer of both ​

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Answered by cr7vishal
1

Answer:

1. First two digit number=10

Last two digit number=99

First two digit number divisible by 6=12

Last two digit number divisible by 6=96

Now the series is:

12,18,24.................................96

18-12=6

24-18=6

This series clearly forms an AP with first term 12 , common difference 6 and last term=96.

a=12

d=6

anth term=96

a+(n-1)d=96

12+(n-1)6=96

6n-6=84

6n=90

n=15

Hence there are 15 two digits number divisible by 6.

Answered by Anonymous
1

Plz check the attachment for your answer ☺️

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