p lez tell me the answer of both
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1. First two digit number=10
Last two digit number=99
First two digit number divisible by 6=12
Last two digit number divisible by 6=96
Now the series is:
12,18,24.................................96
18-12=6
24-18=6
This series clearly forms an AP with first term 12 , common difference 6 and last term=96.
a=12
d=6
anth term=96
a+(n-1)d=96
12+(n-1)6=96
6n-6=84
6n=90
n=15
Hence there are 15 two digits number divisible by 6.
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