Question

p(m)=m²-3√3+1 find p(3√3)​

Answer 1

Answer:

p(m)=m²-3√3+1

Then,

$p(3 \sqrt{3} ) = {(3 \sqrt{3}) }^{2} - 3 \sqrt{3} + 1 \\ = 28 - 3 \sqrt{3}$