Math, asked by kaaysha573, 5 hours ago

p(m)=m²-3m+ 1, find the value of p(1) and p(-1).​

Answers

Answered by danlynmiravel666
1

Answer:

p(E2)=2mn(2m−1)n

Step-by-step explanation:

Let A={a1,a2,...an}

Let S be the sample space and E1 be the event that Pi∩Pj=ϕ for i=j

and E2 be the event that P1∩P2∩...∩Pm=ϕ

Therefore numbers of subsets of A=2n

Therefore each P1,P2,...Pm can be selected in 2n ways

∴n(S)= total number of selection of P1,P2,...Pm=(2n)m=2nm

When P1∩P2∩...∩Pm=ϕ

i.e elements of A does not belong to all the subsets.

There are 2m ways on element does not belong to a subset,

on the other hand, there is only one way the elements can belong to the intersection.

Therefore (2m−1) elements does not belong to the intersection.

n(E

thanks me later!!! labyaaa<♡

Answered by lakshitatuli07
3

Answer:

I)-1

II)5

Step-by-step explanation:

p(m)=m²-3m+ 1

p(1)=1²-3(1)+1

=1-3+1

=-1

p(-1)=-1²-3(-1)+1

=1+3+1

=5

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