Question

P(m)=m2+3m+1 then find the value of the p(1)and p(-1)

Answer 1

Answer:

$\\p(m) =m^2+3m+1$

now substituting the value of 1 in p(m)

$p(1)=(1)^2+3(1)+1\\ =1+3+1\\=5$

now substituting the value of -1 in p(m)

$p(-1)=(-1)^2+3(-1)+1\\= 1-3+1\\= -1$