Math, asked by rishisharma975981, 3 months ago

p^n=(a×5)^n for p^n toend with digit zero a=____ for natural numbers n. (a) any natural number (b) even number (c) odd number (d) none of these.​

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Answered by verdanish63
2

Answer:

p^n=(a×5)^n for p^n toend with digit zero a=____ for natural numbers n.

b) even number

Step-by-step explanation:

Because 5 on multiplying with any number gives 0 in the end.

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