Question

p(n1+n2,2)=90 and p(n1-n2,2)=30, find the value of n1 and n2

Answer 1

If

m and n

are+ve

integers such that

( m+n) p2= 90 and m- np2 = 30

the number of ordered pairs

(m,n)

Answer 2

Answer:

pn1+pn2×p2=90

pn1-pn2×p2=30

30(pn1+pn2×p2)=90(pn1-pn2×p2)

30pn+60pn×30p2=90pn-180pn×90p2

90pn×30p2=-90pn×90p2