P
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Two charges 2uC and 8uC are placed 40 cm
apart then the distance of the point from charge
2uC where total electric field intensity is zero will
be
Answers
Answered by
1
2/x^2 = 8/(12-x)^2
1/x^2 = 4 /(12-x)^2
4 x^2 = 144 - 24 x + x^2
3 x^2 + 24 x - 144 = 0
x^2 + 8 x - 48 = 0
(x+12)(x-4) = 0
x = 4 cm
then 12 - x = 8 cm
check
2/16 = 8/64
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