Physics, asked by kanchanchourasia, 11 months ago

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Two charges 2uC and 8uC are placed 40 cm
apart then the distance of the point from charge
2uC where total electric field intensity is zero will
be​

Answers

Answered by Anonymous
1

2/x^2 = 8/(12-x)^2

1/x^2 = 4 /(12-x)^2

4 x^2 = 144 - 24 x + x^2

3 x^2 + 24 x - 144 = 0

x^2 + 8 x - 48 = 0

(x+12)(x-4) = 0

x = 4 cm

then 12 - x = 8 cm

check

2/16 = 8/64

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