pᴴ of a saturated solution of HCl is 2. what is its solubility product
1 x 10⁻⁴
2 x 10⁻⁴
2 x 10⁻³
1 x 10⁻²
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Answer:
Correct option is D)
Ba(OH)
2
⇄Ba
2+
+2OH
−
pH=12⇒p(OH)=14−pH
→p(OH)=14−12=2
[OH
−
]=10
−POH
=10
−2
or1×10
−2
as conc. of Ba
2+
is half of OH
−
→Ba
2+
=0.5×10
−2
K
sp
=(0.5×10
−2
)(1×10
−2
)
2
K
sp
=0.5×10
−6
=5×10
−7
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