Question

P% of p of p2/3 = 6561000000

Answer 1

Answer:

The value of p is 27000

Step-by-step explanation:

The question is:

If p% of p of p^(2/3) = 6561000000, then what is p?

Solution:

Given

p% of p of p^(2/3) = 6561000000

$\implies \frac{p}{100} \times p\times p^{2/3}=6561000000$

$\implies p\times p\times p^{2/3}=6561000000\times 100$

$\implies p^{(1+1+2/3)}=6561\times 10^8$

$\implies p^{8/3}=6561\times 10^8$

$\implies p^{8/3}=3^8\times 10^8$

$\implies p^{1/3}=3\times 10$

$\implies p^{1/3}=30$

$\implies p=(30)^3$

$\implies p=27000$

Answer 2

Answer:

Value of p = 27000

Step-by-step explanation:

$p\% \:of \:p \: of \: p^{\frac{2}{3}}=6561000000$

$p\% \:\times \:p \: \times \: p^{\frac{2}{3}}=6561000000$

$\frac{p}{100} \:\times \:p \: \times \: p^{\frac{2}{3}}=6561000000$

$\implies p^{1+1+\frac{2}{3}}= 656100000000$

$\implies p^{\frac{3+3+2}{3}}=(30)^{8}$

$\implies p^{\frac{8}{3}}=(30)^{8}$

$\implies p^{\frac{1}{3}}=30$

$\implies p = (30)^{3}$

$\implies p = 27000$

Therefore,

Value of p = 27000

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