Question

P
А
open organ pipe 85cm long is
sounded. If the velocity of sound
& 340ms, what is the fundamental
frequency of vibration of the air coloumn ?​

Answer 1

Answer:

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Explanation:

Answer:

The fundamental frequency is 200 Hz

Explanation:

Given as :

The length of open organ pipe = l = 85 cm = 0.85 m

The velocity of sound = 340 m/s

Let The fundamental frequency = f Hz

According to question

frequency = \dfrac{velocity of sound}{2 length of pipe}

2lengthofpipe

velocityofsound

i.e f = \dfrac{340 m/s}{2 \times 0.85 m}

2×0.85m

340m/s

Or, f = \dfrac{340}{1.7}

1.7

340

∴ f = 200 Hz

So, The fundamental frequency = f = 200 Hz

Hence, The fundamental frequency is 200 Hz Answer

Answer 2

Answer:

the fundamental frequency is200Hz

Explanation:

given as:

the length of open organ pipe=1=85cm =0.85m

the velocity of sound=340m/s

let the fundamental frequency=f Hz

according to question

frequency =

I. e f=

or, f =

therefore f=200Hz

so, the fundamental frequency=f=200 Hz