Question

p(p-2q-n)+2q(p+q+n)-n(3p-q-2n) simplify algebra question​

Answer 1

Answer:

p(p-2q-n)+2q(p+q+n)-n(3p-q-2n)

=$p^2-2p^2-pn+2pq+2q^2+2qn-3pn+nq+2n^2$

=$-p^2 -4pn +2pq+2q^2+3qn+2n^2$

Step-by-step explanation:

Answer 2

$p(p -2q -n) + 2q(p+ q+ n) - n(3p - q - n) = 0$

$({p}^{2} - 2pq - pn) + (2pq + 2 {q}^{2} + 2qn) - (3pn - nq - {n}^{2} ) = 0$

${p}^{2} - 2pq - pn + 2pq + 2 {q}^{2} + 2qn - 3pn + nq + {n}^{2} = 0$

${p}^{2} + 2 {q}^{2} + {n}^{2} - 4pn + 3nq = 0$